Home LeetCode - 191. Number of 1 Bits
Post
Cancel

LeetCode - 191. Number of 1 Bits

191. Number of 1 Bits - easy

문제

Write a function that takes an unsigned integer and returns the number of ‘1’ bits it has (also known as the Hamming weight).

Note:

  • Note that in some languages such as Java, there is no unsigned integer type. In this case, the input will be given as a signed integer type. It should not affect your implementation, as the integer’s internal binary representation is the same, whether it is signed or unsigned.
  • In Java, the compiler represents the signed integers using 2’s complement notation. Therefore, in Example 3 above, the input represents the signed integer. -3.

Follow up: If this function is called many times, how would you optimize it?

제한사항

입출력 예

1
2
3
4
5
Example 1:

Input: n = 00000000000000000000000000001011
Output: 3
Explanation: The input binary string 00000000000000000000000000001011 has a total of three '1' bits.
1
2
3
4
5
Example 2:

Input: n = 00000000000000000000000010000000
Output: 1
Explanation: The input binary string 00000000000000000000000010000000 has a total of one '1' bit.
1
2
3
4
5
Example 3:

Input: n = 11111111111111111111111111111101
Output: 31
Explanation: The input binary string 11111111111111111111111111111101 has a total of thirty one '1' bits.

풀이

  • Bit Manipulate
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
class Solution {
public:
    int hammingWeight(uint32_t n) {
        int count = 0;
        
        while(n) {
            if (n & 1) {
                ++count;
            }
            
            n >>= 1;
        }
        
        return count;
    }
};
This post is licensed under CC BY 4.0 by the author.